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Table 1 Overall design flow of a three-stage two-band QΣΔM

From: Multistage Quadrature Sigma-Delta Modulators for Reconfigurable Multi-Band Analog-Digital Interface in Cognitive Radio Devices

Preliminary spectrum information

   1. Obtain the center frequencies (fC,1 and fC,2 ) and the suitable frequency offsets (foffset,1 and foffset,2) based on the bandwidths of the desired signals, e.g., from [36]

   2. Based on the spectrum sensing information, find the most harmful blockers (fint,1 and fint,2 )

• In case of mirror-frequency rejecting STF design fint,1 = −fC,1 and fint,2 = −fC,2

Design of a three-stage two-band QΣΔM with mirror-frequency rejecting first-stage STF

Transfer function design for the first-stage (two-band NTF and mirror-frequency rejecting STF)

   1. Place the NTF zeros: φ NTF . 1 ( 1 ) = e j 2 π f C,1 T S , φ NTF . 2 ( 1 ) = e j 2 π f C,2 T S

   2. Place the STF zeros: φ STF . 1 ( 1 ) = e j 2 π f int , 1 T S , φ NTF . 2 ( 1 ) = e j 2 π f int , 2 T S

   3. Place the common poles: ψ common 1 ( 1 ) = 0 . 5 e j 2 π f C , 1 T S and ψ common . 2 ( 1 ) =0.5 e j 2 π f C , 2 T S

   4. Solve the modulator coefficients M(1) N(1) using (51)-(52); A(1), B(2) and C(1) using (54)-(56); and R(1) and S(1) using (58)-(59).

Transfer function design for the second-stage (two-band NTF and frequency-flat STF)

   5. Place the NTF zeros: φ NTF . 1 ( 2 ) = e j 2 π ( f C, 1 + f offset,1 ) T S , φ NTF . 2 ( 2 ) = e j 2 π ( f C, 2 + f offset , 2 ) T S

   6. Place the STF zeros: φ STF 1 ( 2 ) = 0 , φ NTF . 2 ( 2 ) = 0

   7. Place the common poles: ψ common . 1 ( 2 ) = 0 and ψ common . 2 ( 2 ) = 0

   8. Solve the modulator coefficients M(2) and N(2) using (51)-(52); A(2), B(2) and C(2) using (54)-(56); and R(2)and S(2) using (58)-(59).

Transfer function design for the third-stage (two-band NTF and frequency-flat STF)

   9. Place the NTF zeros: φ NTF .1 ( 3 ) = e j 2 π ( f C . 1 - f o ffset,1 ) T S , φ NTF .1 ( 3 ) = e j 2 π ( f C , 2 - f offset,2 ) T S

   10. Place the STF zeros: φ STF 1 ( 3 ) = 0 , φ NTF . 2 ( 3 ) = 0

   11. Place the common poles: ψ common . 1 ( 3 ) = 0 and ψ common . 2 ( 3 ) = 0

   12. Solve the modulator coefficients M(3) and N(3) using (51)-(52); A(3), B(3) and C(3) using (54)-(56); and R(3) and S(3) (58)-(59).